Two parents display different phenotypes for a given trait that is encoded by a single gene. All their offspring (of which there are hundreds) share a phenotype, but it differs from that of either parent. You would be justified in concluding that…

1. both parents were heterozygous for the gene that controls the trait.
2. both parents were homozygous for the gene that controls the trait.
3. one parent was heterozygous, the other was homozygous for the gene
4. that controls the trait.
5. a recombination event has occurred in one or both parents.

22. Gene A and gene B are located on the same chromosome. Consider the following cross: AB/ab X ab/ab. Under what conditions would you expect to find 25% of the individuals with an Ab/ab genotype?

1. It cannot happen because the A and B genes are linked.
2. It will always occur, because of independent assortment.
3. It will occur only when the genes are far away from one another.
4. It will occur only when the genes are close enough for recombination to
5. occur between them.