The equation of line A is 3x+6y-1=0 give the equation of a line that passed through point (5,1) that is perpendicular to line A 2. | Cheap Nursing Papers
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The equation of line A is 3x+6y-1=0 give the equation of a line that passed through point (5,1) that is perpendicular to line A 2.

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The equation of line A is 3x+6y-1=0 give the equation of a line that passed through point (5,1) that is

  1. perpendicular to line A
  2. 2. parallel to line A

please give the explanations to the answer so I understand how to get it!

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