t1 = x b. t2 = (y. t3 = (x.(x y)) d. t4 = ((x.y) x) e. t5 = y.wyzx d. t6 = x. t7 = ((((x.x)z)x)(( y. | Cheap Nursing Papers

t1 = x b. t2 = (y. t3 = (x.(x y)) d. t4 = ((x.y) x) e. t5 = y.wyzx d. t6 = x. t7 = ((((x.x)z)x)(( y.

a. t1 = x 

b. t2 = (λy.y) 

c. t3 = (λx.(x y)) 

d. t4 = ((λx.y) x) 

e. t5 = λy.w λw.wyzx 

d. t6 = λx.xz λy.xy 

f. t7 = ((((λx.x)z)x)(( λy.(z y))y))  

Using the terms from above, apply the following substitutions and show the resulting expression: 

a. t1[x := t2] 

b. t2[y := 5] 

c. t4[x := t3] 

d. t6[y := t5] 

e. t7[z := t2] 

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