m earth = 5.9742 x 10 24 kg r earth = 6.3781 x 10 6 m m moon = 7.36 x 10 22 kg r moon = 1.7374 x 10 6 m d earth to moon = 3.844 x 10 8 m (center to… | Cheap Nursing Papers

m earth = 5.9742 x 10 24 kg r earth = 6.3781 x 10 6 m m moon = 7.36 x 10 22 kg r moon = 1.7374 x 10 6 m d earth to moon = 3.844 x 10 8 m (center to…

Please help me to solve it:

mearth = 5.9742 x 1024 kg

rearth = 6.3781 x 106 m

mmoon = 7.36 x 1022 kg

rmoon = 1.7374 x 106 m

dearth to moon = 3.844 x 108 m (center to center)

G = 6.67428 x 10-11 N-m2/kg2

A 1500 kg satellite is orbitting the earth in a circular orbit with an altitude of 1500 km.

1) How much energy does it take just to get it to this altitude?

2) How much kinetic energy does it have once it has reached this altitude?

3) What is the ratio of the this change in potential energy to the change in kinetic energy? (i.e. what is (a)/(b)?)

4) What would this ratio be if the final altitude of the satellite were 4200 km?

5) What would this ratio be if the final altitude of the satellite were 3185 km?

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