I am supposed to figure out how many moles of MnO4 – ions reacted with the given amount of oxalic acid solution with this given information -> A sample of oxalic acid is titrated with a standardized solution of KMNO4. A 25 mL sample of oxalic acid required 12.30 mL of 0.0226 M KMnO4 to achieve a pink colored solution. The balanced equation for this reaction is shown below.

6 H+ (aq) + 2 MnO4 – (aq) + 5 H2C2O4(aq) → 10 CO2(g) +8 H2O(l) + 2Mn2+(aq)