I am having trouble figuring out a chemistry question on how to balance a redox reaction using the half-reaction method.

Published by admin at November 14, 2023

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2H2O + NO –> NO3- + 4H+

2H2O + NO –> NO3- + 4H+ +3e-

Step 6. Multiply both of the half-reactions by a whole number so that the number of electrons gained and lost is equal.

14H++Cr2O72- + 6e- –> 2Cr3+ + 7H2O

2H2O + NO –> NO3- + 4H+ +3e- X 2 [because 2X3= 6 electrons]

4H2O + 2NO –> 2NO3- +8H+ +6e-

Step 7. Add the half-reactions. Subtract any chemicals that are common to both sides.

Cr2O72- + 2NO+6H+ –> 2Cr3+ + 2NO3-+ 3H2O