For a cell Zn + CU ++ –gt; Zn ++ + Cu, E 0 = 1. | Cheap Nursing Papers

For a cell Zn + CU ++ –gt; Zn ++ + Cu, E 0 = 1.

For a cell Zn + CU++ –> Zn++ + Cu, E0 = 1.10 v, initially having unit activities of both Cu++ and Zn++, assume that current is drawn so that the concentration of Cu++ is reduced by 1% per hour. What would be the value of E after 1, 2, and 10 hours?

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