Find the enthalpy change for the chemical reaction below PCl5(g) —-> PCl3 (g) +Cl2 From the following equations: P4 (s) + 6Cl2(g) —-> 4PCl3(g) DeltaH = -2439 kJ 4PCl3(g) —-> P4 +10Cl2 (g) Delta H = 3438 kJ
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