Can you explain How you got the total ways answer in detail ?

electing 5 out of 59 values followed by selection of 1 out of 39 values

Total ways = 59C5 X 39C1

But,

59C5=59!/(59-5)!*5!

59C5=5,006,386

39C1 =39!/(39-1)!*1!

39C1 =39

Total ways=5,006,386*39

Total ways=195,249,054

Out of all ways only one is favorable

Therefore the probability of correctly guessing all 6 values with just one ticket is 1/ 195,249,054

Thank you