At a certain temperature K = 1.10×103 for the reaction:
Fe3+(aq) + SCN-(aq) FeSCN2+(aq)
8.00×10-2 mol of Fe(NO3)3 is added to 1.02 L of 1.27×10-1 M KSCN.
Neglecting any volume change and assuming that all species remain in solution–:
Calculate the equilibrium concentration of Fe3+ (in mol/
i tried many times but didnot got the correct answer.. the answer I got is 0.002
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