Acid Base titration Lab: Add NaOH to a hot sauce mixture, then to a ketchup mixture. ****The hot sauce mixture consisted of 20 mL DH20 AND 1.5g Hot sauce. Ketchup = 20 mL DH20 and 1.5 g ketchup. the below columns are the mLs added of NaOH, and the pH value at each point. 3rd column is derivative

A.) For each trial calculate mol NaOH needed to reach equiv. point, and the average concentration of C2H4O2 in each trial.

B.) What is the concentration of NaOH used (M) in each trial?

HOT SAUCE TRIAL-

mL pH derivative

0.00 3.50 0.49

0.5 3.76 0.44

1.0 3.98 0.37

1.5 4.13 0.31

2.0 4.27 0.26

2.5 4.39 0.24

3.0 4.50 0.23

3.5 4.62 0.23

3.75 4.68 0.22

4.0 4.73 0.21

4.25 4.78 0.21

4.5 4.83 0.22

4.75 4.89 0.23

5.0 4.95 0.23

5.25 5.01 0.24

5.5 5.07 0.26

5.75 5.13 0.28

6.0 5.21 0.31

6.25 5.29 0.33

6.5 5.37 0.37

6.75 5.47 0.44

7.0 5.58 0.54

7.25 5.72 0.73

7.5 5.93 1.13

7.75 6.20 2.00

8.0 6.70 3.59

8.25 8.05 4.84

8.5 9.60 4.25

8.75 10.38 2.75

9.0 10.83 1.59

9.25 11.09 0.90

9.5 11.27 0.55

10.0 11.49 0.39

10.5 11.64 0.30

11.0 11.75 0.24

KETCHUP TRIAL:

mL pH Derivative

0.0 3.95 0.50

0.5 4.21 0.49

1.0 4.45 0.48

1.5 4.68 0.47

2.0 4.91 0.49

2.25 5.04 0.56

2.5 5.19 0.66

2.75 5.36 0.85

3.0 5.59 1.26

3.25 5.89 2.12

3.5 6.45 3.57

3.75 7.85 4.28

4.0 9.01 3.42

4.25 9.61 2.22

4.5 9.98 1.42

4.75 10.26 0.96

5.0 10.47 0.67

5.5 10.75 0.52

6.0 10.94 0.44